python arguments

import sys
print("This is the name of the script:", sys.argv[0])
print("Number of arguments:", len(sys.argv))
print("The arguments are:" , str(sys.argv))

#Example output
#This is the name of the script: sysargv.py
#Number of arguments in: 3
#The arguments are: ['sysargv.py', 'arg1', 'arg2']

 1 # argv.py
 2 import sys
 3 
 4 print(f"Name of the script      : {sys.argv[0]=}")
 5 print(f"Arguments of the script : {sys.argv[1:]=}")

import sys

def hello(a,b):
    print "hello and that's your sum:", a + b

if __name__ == "__main__":
    a = int(sys.argv[1])
    b = int(sys.argv[2])
    hello(a, b)
# If you type : py main.py 1 5
# It should give you "hello and that's your sum:6"

import sys

print ("the script has the name %s" % (sys.argv[0])

#!/usr/bin/python

import sys

print 'Number of arguments:', len(sys.argv), 'arguments.'
print 'Argument List:', str(sys.argv)

#Terminal
# $ python test.py arg1 arg2 arg3

#print
#Number of arguments: 4 arguments.
#Argument List: ['test.py', 'arg1', 'arg2', 'arg3']

#!/usr/bin/python

import sys

print('Number of arguments:', len(sys.argv), 'arguments.')
print('Argument List:', str(sys.argv))

#!/usr/bin/python

import sys

print 'Number of arguments:', len(sys.argv), 'arguments.'
print 'Argument List:', str(sys.argv)

#!/usr/bin/python

import sys, getopt

def main(argv):
   inputfile = ''
   outputfile = ''
   try:
      opts, args = getopt.getopt(argv,"hi:o:",["ifile=","ofile="])
   except getopt.GetoptError:
      print 'test.py -i <inputfile> -o <outputfile>'
      sys.exit(2)
   for opt, arg in opts:
      if opt == '-h':
         print 'test.py -i <inputfile> -o <outputfile>'
         sys.exit()
      elif opt in ("-i", "--ifile"):
         inputfile = arg
      elif opt in ("-o", "--ofile"):
         outputfile = arg
   print 'Input file is "', inputfile
   print 'Output file is "', outputfile

if __name__ == "__main__":
   main(sys.argv[1:])

#*args and **kwargs are normally used as arguments when calling the function.

#*args returns as tuple and **kwargs returns as dictionary.

#*args and **kwargs  let you write functions with variable number of arguments in python.

def func(required,*args,**kwargs):
    return f"{required} {args} {kwargs}"
  
func("Nagendra",5,32,2,1,23,) #output == 'Nagendra (5, 32, 2, 1, 23) {}'
func("Nagendra",5,32,2,1,23,key1="55",key2="75") #output == "Nagendra (5, 32, 2, 1, 23) {'key1': '55', 'key2': '75'}"

#Very understable example of args.
#Given n number of arguments in a function calculate its average
def average(*args):
  '''
  As we already know *args means collection of values in a tuple.
  INPUT: arguments are given. example average(4,10,) 
  OUTPUT: average of two numbers (4+10)/2 == 14
  '''
  return sum(args)/len(args)

average(1,2,3,4,5,6,7,8,9,10,11,12,13,14,15) #output == 8.0

# Python program to demonstrate 
# command line arguments 
  
  
import getopt, sys 
  
  
# Remove 1st argument from the 
# list of command line arguments 
argumentList = sys.argv[1:] 
  
# Options 
options = "hmo:"
  
# Long options 
long_options = ["Help", "My_file", "Output ="] 
  
try: 
    # Parsing argument 
    arguments, values = getopt.getopt(argumentList, options, long_options) 
      
    # checking each argument 
    for currentArgument, currentValue in arguments: 
  
        if currentArgument in ("-h", "--Help"): 
            print ("Diplaying Help") 
              
        elif currentArgument in ("-m", "--My_file"): 
            print ("Displaying file_name:", sys.argv[0]) 
              
        elif currentArgument in ("-o", "--Output"): 
            print (("Enabling special output mode (% s)") % (currentValue)) 
              
except getopt.error as err: 
    # output error, and return with an error code 
    print (str(err))