getting command line arguments in python

import sys
print("This is the name of the script:", sys.argv[0])
print("Number of arguments:", len(sys.argv))
print("The arguments are:" , str(sys.argv))

#Example output
#This is the name of the script: sysargv.py
#Number of arguments in: 3
#The arguments are: ['sysargv.py', 'arg1', 'arg2']

#!/usr/bin/python

import sys

print 'Number of arguments:', len(sys.argv), 'arguments.'
print 'Argument List:', str(sys.argv)

# Python program to demonstrate 
# command line arguments 
  
  
import getopt, sys 
  
  
# Remove 1st argument from the 
# list of command line arguments 
argumentList = sys.argv[1:] 
  
# Options 
options = "hmo:"
  
# Long options 
long_options = ["Help", "My_file", "Output ="] 
  
try: 
    # Parsing argument 
    arguments, values = getopt.getopt(argumentList, options, long_options) 
      
    # checking each argument 
    for currentArgument, currentValue in arguments: 
  
        if currentArgument in ("-h", "--Help"): 
            print ("Diplaying Help") 
              
        elif currentArgument in ("-m", "--My_file"): 
            print ("Displaying file_name:", sys.argv[0]) 
              
        elif currentArgument in ("-o", "--Output"): 
            print (("Enabling special output mode (% s)") % (currentValue)) 
              
except getopt.error as err: 
    # output error, and return with an error code 
    print (str(err))