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Q:

program arguments python

import sys
print("This is the name of the script:", sys.argv[0])
print("Number of arguments:", len(sys.argv))
print("The arguments are:" , str(sys.argv))

#Example output
#This is the name of the script: sysargv.py
#Number of arguments in: 3
#The arguments are: ['sysargv.py', 'arg1', 'arg2']
17
import sys

def hello(a,b):
    print "hello and that's your sum:", a + b

if __name__ == "__main__":
    a = int(sys.argv[1])
    b = int(sys.argv[2])
    hello(a, b)
# If you type : py main.py 1 5
# It should give you "hello and that's your sum:6"
6
import sys

print ("the script has the name %s" % (sys.argv[0])
3
#!/usr/bin/python

import sys

print 'Number of arguments:', len(sys.argv), 'arguments.'
print 'Argument List:', str(sys.argv)

#Terminal
# $ python test.py arg1 arg2 arg3

#print
#Number of arguments: 4 arguments.
#Argument List: ['test.py', 'arg1', 'arg2', 'arg3']

10
#!/usr/bin/python

import sys

print('Number of arguments:', len(sys.argv), 'arguments.')
print('Argument List:', str(sys.argv))
7
#!/usr/bin/python

import sys

for args in sys.argv:
  print(args)

"""
If you were to call the program with subsequent arguments, the output 
will be of the following
Call:
python3 sys.py homie no

Output:
sys.py
homie
no
"""
2
#!/usr/bin/python

import sys

print 'Number of arguments:', len(sys.argv), 'arguments.'
print 'Argument List:', str(sys.argv)
3
#!/usr/bin/python

import sys, getopt

def main(argv):
   inputfile = ''
   outputfile = ''
   try:
      opts, args = getopt.getopt(argv,"hi:o:",["ifile=","ofile="])
   except getopt.GetoptError:
      print 'test.py -i <inputfile> -o <outputfile>'
      sys.exit(2)
   for opt, arg in opts:
      if opt == '-h':
         print 'test.py -i <inputfile> -o <outputfile>'
         sys.exit()
      elif opt in ("-i", "--ifile"):
         inputfile = arg
      elif opt in ("-o", "--ofile"):
         outputfile = arg
   print 'Input file is "', inputfile
   print 'Output file is "', outputfile

if __name__ == "__main__":
   main(sys.argv[1:])
1
# Python program to demonstrate 
# command line arguments 
  
  
import getopt, sys 
  
  
# Remove 1st argument from the 
# list of command line arguments 
argumentList = sys.argv[1:] 
  
# Options 
options = "hmo:"
  
# Long options 
long_options = ["Help", "My_file", "Output ="] 
  
try: 
    # Parsing argument 
    arguments, values = getopt.getopt(argumentList, options, long_options) 
      
    # checking each argument 
    for currentArgument, currentValue in arguments: 
  
        if currentArgument in ("-h", "--Help"): 
            print ("Diplaying Help") 
              
        elif currentArgument in ("-m", "--My_file"): 
            print ("Displaying file_name:", sys.argv[0]) 
              
        elif currentArgument in ("-o", "--Output"): 
            print (("Enabling special output mode (% s)") % (currentValue)) 
              
except getopt.error as err: 
    # output error, and return with an error code 
    print (str(err)) 
0
import argparse

parser = argparse.ArgumentParser(description='Process some integers.')
parser.add_argument('integers', metavar='N', type=int, nargs='+',
                   help='an integer for the accumulator')
parser.add_argument('--sum', dest='accumulate', action='store_const',
                   const=sum, default=max,
                   help='sum the integers (default: find the max)')

args = parser.parse_args()
print(args.accumulate(args.integers))
-1

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