ckruczek
0
Q:

zip function python 3

>>> numbers = [1, 2, 3]
>>> letters = ['a', 'b', 'c']
>>> zipped = zip(numbers, letters)
>>> zipped  # Holds an iterator object
<zip object at 0x7fa4831153c8>
>>> type(zipped)
<class 'zip'>
>>> list(zipped)
[(1, 'a'), (2, 'b'), (3, 'c')]  #list of tuples  
# zip returns tuples
27
>>> x = [1, 2, 3]
>>> y = [4, 5, 6]
>>> zipped = zip(x, y)
>>> list(zipped)
[(1, 4), (2, 5), (3, 6)]
>>> x2, y2 = zip(*zip(x, y))
>>> x == list(x2) and y == list(y2)
True
10
>>> letters = ['a', 'b', 'c']
>>> numbers = [0, 1, 2]
>>> for l, n in zip(letters, numbers):
...     print(f'Letter: {l}')
...     print(f'Number: {n}')
...
Letter: a
Number: 0
Letter: b
Number: 1
Letter: c
Number: 2
1
number_list = [1, 2, 3]
str_list = ['one', 'two', 'three']

# No iterables are passed
result = zip()

# Converting itertor to list
result_list = list(result)
print(result_list)

# Two iterables are passed
result = zip(number_list, str_list)

# Converting itertor to set
result_set = set(result)
print(result_set)

>>>[]
{(2, 'two'), (3, 'three'), (1, 'one')}
1

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