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Q:

extarct zip in python

# importing required modules 
from zipfile import ZipFile 
  
# specifying the zip file name 
file_name = "my_python_files.zip"
  
# opening the zip file in READ mode 
with ZipFile(file_name, 'r') as zip: 
    # printing all the contents of the zip file 
    zip.printdir() 
  
    # extracting all the files 
    print('Extracting all the files now...') 
    zip.extractall() 
    print('Done!') 
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import zipfile
def un_zipFiles(path):
    files=os.listdir(path)
    for file in files:
        if file.endswith('.zip'):
            filePath=path+'/'+file
            zip_file = zipfile.ZipFile(filePath)
            for names in zip_file.namelist():
                zip_file.extract(names,path)
            zip_file.close() 
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import os
import optparse
import zipfile

def get_arguments():
    parser = optparse.OptionParser()
    parser.add_option("--src","--source",dest="paths", help="Removing file with extension .SRT and .VTT")
    (options,arguments)=parser.parse_args()
    if not options.paths:
        parser.error("[-] Please specify source, use --help for more info.")
    return options


def Source_folder(folder_path):
    print('[+] Extracting zip file')
    for path, dir_list, file_list in os.walk(folder_path):
        try:
            for file_name in file_list:
                if file_name.endswith(".zip"):
                    abs_file_path = os.path.join(path, file_name)
                    parent_path = os.path.split(abs_file_path)[0]
                    output_folder_name = os.path.splitext(abs_file_path)[0]
                    output_path = os.path.join(parent_path, output_folder_name)

                    zip_obj = zipfile.ZipFile(abs_file_path, 'r')
                    zip_obj.extractall(output_path)
                    zip_obj.close()

        except FileNotFoundError:
            print('Error', file_name)


options = get_arguments()
Source_folder(options.paths)
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