# True since 1,3 and 4 (at least one) is true l = [1, 3, 4, 0] print(any(l)) # False since both are False l = [0, False] print(any(l)) # True since 5 is true l = [0, False, 5] print(any(l)) # False since iterable is empty l = [] print(any(l))
