Q:

all in python

	
    mylist = [0, 1, 1]
	# returns if all item in the list is True, same for empty list
    
    x = all(mylist)
    
    # returns False
    
    
   
9
'''
Return Value from all()
all() method returns:

True - If all elements in an iterable are true
False - If any element in an iterable is false
'''

# all values true
l = [1, 3, 4, 5]
print(all(l))            # Result : True

# all values false
l = [0, False]
print(all(l))			 # Result : False

# one false value ( As 0 is considered as False)
l = [1, 3, 4, 0]
print(all(l))			 # Result : False

# one true value
l = [0, False, 5]
print(all(l))			 # Result : False

# empty iterable
l = []
print(all(l))
3
# Since all are false, false is returned 
print (any([False, False, False, False])) 
  
# Here the method will short-circuit at the 
# second item (True) and will return True. 
print (any([False, True, False, False])) 
  
# Here the method will short-circuit at the 
# first (True) and will return True. 
print (any([True, False, False, False])) 
1
# Here all the iterables are True so all 
# will return True and the same will be printed 
print (all([True, True, True, True])) 
  
# Here the method will short-circuit at the  
# first item (False) and will return False. 
print (all([False, True, True, False])) 
  
# This statement will return False, as no 
# True is found in the iterables 
print (all([False, False, False])) 
0

New to Communities?

Join the community