Q:

number Bubble sort python

def bubbleSort(lis):
    length = len(lis)
    for i in range(length):
        for j in range(length - i):
            a = lis[j]
            if a != lis[-1]:
                b = lis[j + 1]
                if a > b:
                    lis[j] = b
                    lis[j + 1] = a
    return lis
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# Python program for implementation of Bubble Sort 

def bubbleSort(arr): 
	n = len(arr) 

	# Traverse through all array elements 
	for i in range(n-1): 
	# range(n) also work but outer loop will repeat one time more than needed. 

		# Last i elements are already in place 
		for j in range(0, n-i-1): 

			# traverse the array from 0 to n-i-1 
			# Swap if the element found is greater 
			# than the next element 
			if arr[j] > arr[j+1] : 
				arr[j], arr[j+1] = arr[j+1], arr[j] 

# Driver code to test above 
arr = [64, 34, 25, 12, 22, 11, 90] 

bubbleSort(arr) 

print ("Sorted array is:") 
for i in range(len(arr)): 
	print ("%d" %arr[i]), 
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