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Q:

sort in python'

numbers = [1, 3, 4, 2] 
  
# Sorting list of Integers in ascending in place
numbers.sort() 
  
print(numbers) 
6
>>> x = [1 ,11, 2, 3]
>>> y = sorted(x)
>>> x
[1, 11, 2, 3]
>>> y
[1, 2, 3, 11]
2
strs = ["geeks", "code", "ide", "practice"] 
  
# Sorting list of Integers in ascending 
strs.sort() 
  
print(strs) 
2
>>> student_tuples = [
...     ('john', 'A', 15),
...     ('jane', 'B', 12),
...     ('dave', 'B', 10),
... ]
>>> sorted(student_tuples, key=lambda student: student[2])   # sort by age
[('dave', 'B', 10), ('jane', 'B', 12), ('john', 'A', 15)]
4
arr = [1,4,2,7,5,6]
#sort in ascending order
arr = arr.sort() 

#sort in descending order
arr = arr.sort(reverse = True)
1
nums = [4,8,5,2,1]
#1 sorted() (Returns sorted list)
sorted_nums = sorted(nums)
print(sorted_nums)#[1,2,4,5,8]
print(nums)#[4,8,5,2,1]

#2 .sort() (Changes original list)
nums.sort()
print(nums)#[1,2,4,5,8]
3
List_name.sort()
This will sort the given list in ascending order.
1
old_list = [3,2,1]
old_list.sort()
1
list.sort([func])
0
python list sort()
0

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