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Q:

np.tile

a = np.array([0, 1, 2])

np.tile(a, 2)
#output ([0, 1, 2, 0, 1, 2])
np.tile(a, (2, 2))
#output  ([[0, 1, 2, 0, 1, 2], [0, 1, 2, 0, 1, 2]])

np.tile(a, (2, 1, 2))
#output ([[[0, 1, 2, 0, 1, 2]], [[0, 1, 2, 0, 1, 2]]])

b = np.array([[1, 2], [3, 4]])
np.tile(b, 2)
#output ([[1, 2, 1, 2], [3, 4, 3, 4]])
np.tile(b, (2, 1))
#output ([[1, 2], [3, 4], [1, 2], [3, 4]])
1
>>> a = np.array([0, 1, 2])
>>> np.tile(a, 2)
array([0, 1, 2, 0, 1, 2])
>>> np.tile(a, (2, 2))
array([[0, 1, 2, 0, 1, 2],
       [0, 1, 2, 0, 1, 2]])
>>> np.tile(a, (2, 1, 2))
array([[[0, 1, 2, 0, 1, 2]],
       [[0, 1, 2, 0, 1, 2]]])
0

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