max element in array

// For large data, it's better to use reduce. Supose arr has a large data in this case:
const arr = [1, 5, 3, 5, 2];
const max = arr.reduce((a, b) => { return Math.max(a, b) });

// For arrays with relatively few elements you can use apply: 
const max = Math.max.apply(null, arr);

// or spread operator:
const max = Math.max(...arr);

#include <stdio.h>
int main() {
    int i, n;
    float arr[100];
    printf("Enter the number of elements (1 to 100): ");
    scanf("%d", &n);

    for (i = 0; i < n; ++i) {
        printf("Enter number%d: ", i + 1);
        scanf("%f", &arr[i]);
    }

    // storing the largest number to arr[0]
    for (i = 1; i < n; ++i) {
        if (arr[0] < arr[i])
            arr[0] = arr[i];
    }

    printf("Largest element = %.2f", arr[0]);

    return 0;
}

let numbers = [4, 13, 27, 0, -5]; // Get max value of an array in Javascript

Math.max.apply(null, numbers); // returns 27

int max;
max=INT_MIN;

for(int i=0;i<ar.length();i++){
	if(ar[i]>max){
    	max=ar[i];
    }

       

def return_largest_element(array):
    largest = 0
    for x in range(0, len(array)):
        if(array[x] > largest):
            largest = array[x]
    return largest

int[] a = new int[] { 20, 30, 50, 4, 71, 100};
		int max = a[0];
		for(int i = 1; i < a.length;i++)
		{
			if(a[i] > max)
			{
				max = a[i];
			}
		}
		
		System.out.println("The Given Array Element is:");
		for(int i = 0; i < a.length;i++)
		{
			System.out.println(a[i]);
		}
		
		System.out.println("From The Array Element Largest Number is:" + max);

Input : arr[] = {10, 20, 4}
Output : 20

Input : arr[] = {20, 10, 20, 4, 100}
Output : 100