longest common substring
// C++ program using to find length of the
// longest common substring recursion
#include <iostream>
using namespace std;
string X,Y;
// Returns length of function for longest common
// substring of X[0..m-1] and Y[0..n-1]
int lcs(int i, int j, int count)
{
if (i == 0 || j == 0)
return count;
if (X[i-1] == Y[j-1]) {
count = lcs(i - 1, j - 1, count + 1);
}
count = max(count, max(lcs( i, j - 1, 0), lcs( i - 1, j, 0)));
return count;
}
// Driver code
int main()
{
int n,m;
X = "abcdxyz";
Y = "xyzabcd";
n=X.size();
m=Y.size();
cout<<lcs(n,m,0);
return 0;
}
/* Dynamic Programming solution to find length of the
longest common substring */
#include<iostream>
#include<string.h>
using namespace std;
/* Returns length of longest common substring of X[0..m-1]
and Y[0..n-1] */
int LCSubStr(char *X, char *Y, int m, int n)
{
// Create a table to store lengths of longest
// common suffixes of substrings. Note that
// LCSuff[i][j] contains length of longest
// common suffix of X[0..i-1] and Y[0..j-1].
int LCSuff[m+1][n+1];
int result = 0; // To store length of the
// longest common substring
/* Following steps build LCSuff[m+1][n+1] in
bottom up fashion. */
for (int i=0; i<=m; i++)
{
for (int j=0; j<=n; j++)
{
// The first row and first column
// entries have no logical meaning,
// they are used only for simplicity
// of program
if (i == 0 || j == 0)
LCSuff[i][j] = 0;
else if (X[i-1] == Y[j-1])
{
LCSuff[i][j] = LCSuff[i-1][j-1] + 1;
result = max(result, LCSuff[i][j]);
}
else LCSuff[i][j] = 0;
}
}
return result;
}
/* Driver program to test above function */
int main()
{
char X[] = "OldSite:GeeksforGeeks.org";
char Y[] = "NewSite:GeeksQuiz.com";
int m = strlen(X);
int n = strlen(Y);
cout << "Length of Longest Common Substring is "
<< LCSubStr(X, Y, m, n);
return 0;
}