how to print value of pointer in c

#include <stdio.h>
int main() {
    int data[5];

    printf("Enter elements: ");
    for (int i = 0; i < 5; ++i)
        scanf("%d", data + i);

    printf("You entered: \n");
    for (int i = 0; i < 5; ++i)
        printf("%d\n", *(data + i));
    return 0;
}

int a = 42;

printf("%p\n", (void *) &a);

#include <stdio.h>
#include <stdlib.h>

void pointerFuncA(int* iptr){
/*Print the value pointed to by iptr*/
printf("Value:  %d\n", *iptr );

/*Print the address pointed to by iptr*/
printf("Value:  %p\n", iptr );

/*Print the address of iptr itself*/
printf("Value:  %p\n", &iptr );
}

int main(){
int i = 1234; //Create a variable to get the address of
int* foo = &i; //Get the address of the variable named i and pass it to the integer pointer named foo
pointerFuncA(foo); //Pass foo to the function. See I removed void here because we are not declaring a function, but calling it.

return 0;
}