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Q:

es6 reduce return promise

async function slowCounter () {
    const ret = await ([100, 200, 300, 400, 500]).reduce(
        async (promise, wait, idx) => {
            return promise.then(async last => {
                const ret = last + wait
                console.log(`${idx}: waiting ${wait}ms to return ${ret}`)
                await new Promise((res, rej) => setTimeout(res, wait))
                return ret
            })
        }, Promise.resolve(0))
    console.log(ret)
}

slowCounter ()
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