Split python

kilimanjaro

Code: Python

2021-02-15 01:41:32

persoonsgegevens = "Clarissa Smet, Aktorstraat 12, 3000 Leuven"
txt.split(",")

# Output:
# ["Clarissa Smet", "Aktorstraat 12", "3000 Leuven"]

3

user11243

Code: Python

2021-02-07 06:22:11

string = 'James Smith Bond'
x = string.split(' ') #Splits every ' ' (space) in the string to a list
# x = ['James','Smith','Bond']
print('The name is',x[-1],',',x[0],x[-1])

2

mondegreen dispenser

Code: Python

2021-06-23 23:24:27

# Basic syntax:
string.split("text_to_split_by")

# Example usage:
text = "this|is|an|example"
print(text.split("|"))
--> ['this', 'is', 'an', 'example']

2

Muzamil Ali

Code: Python

2021-02-07 06:19:27

>>> '1,2,3'.split(',')
['1', '2', '3']
>>> '1,2,3'.split(',', maxsplit=1)
['1', '2,3']
>>> '1,2,,3,'.split(',')
['1', '2', '', '3', '']

1

Purich W.

Code: Python

2021-02-20 14:34:13

file='/home/folder/subfolder/my_file.txt'
file_name=file.split('/')[-1].split('.')[0]

15

j4eo

Code: Python

2021-02-07 06:21:37

import pandas as pd
row , coloumn = df.shape
year = [2012,2103,2014,2015]

for i in range(0,row) :
  if df.iloc[i]['A'] =="task1" or df.iloc[i]['A'] == "task2"  :
    if df.iloc[i]['B'] in year and df.iloc[i]['B'] >= 7:
      print(df.iloc[i]['C'])

-1

Hadzher

Code: Python

2021-02-07 06:20:17

filename = input("Input the Filename: ")
f_extns = filename.split(".")
print ("The extension of the file is : " + repr(f_extns[-1]))

-2

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