sort reverse python

#1 Changes list
list.sort(reverse=True)
#2 Returns sorted list
sorted(list, reverse=True)

# sort() will change the original list into a sorted list
vowels = ['e', 'a', 'u', 'o', 'i']
vowels.sort()
# Output:
# ['a', 'e', 'i', 'o', 'u']

# sorted() will sort the list and return it while keeping the original
sortedVowels = sorted(vowels)
# Output:
# ['a', 'e', 'i', 'o', 'u']

# defning A as a list
A.sort(reverse = True)

sorted(iterable, key=None, reverse=False)

type(sorted(iterable, key=None, reverse=False)) = list

numbers = [1, 3, 4, 2] 
  
# Sorting list of Integers in descending 
numbers.sort(reverse = True) 
  
print(numbers) 

strs = ["geeks", "code", "ide", "practice"] 
  
# Sorting list of Integers in ascending 
strs.sort() 
  
print(strs) 

>>> student_tuples = [
...     ('john', 'A', 15),
...     ('jane', 'B', 12),
...     ('dave', 'B', 10),
... ]
>>> sorted(student_tuples, key=lambda student: student[2])   # sort by age
[('dave', 'B', 10), ('jane', 'B', 12), ('john', 'A', 15)]

sorted(list, key=..., reverse=...)

list.sort(reverse=True)