reverse for loop in python

n = 4
#works with int and arr
for x in reversed(range(n)):
  print(x)
 
#for int you can have range(start, stop, step)
for x in range(0, n, -1):
  print(x)
  

# 1.
for i in reversed(range(3)): # output: 	0
    print(i)				 #			1
    						 # 			2
# works with arrays as well , reversed(arr)

# 2.
# another alternative is
arr = [1,2,3]
# note: arr[start : end : step]
for i in arr[::-1]:			 # output:	0
  print(i)					 # 			1
  							 #			2

# 3.
# last alternative i don't recommened!
# note: range(start, end, step)
for i in range(len(arr) - 1, -1 , -1): 	# output: 	0
  print(i)								# 			1
  										# 			2
# read more on range() to understand even better how it works has the same rules as the arrays

    for i in range(len(item)-1, -1, -1):
        print(item[i])

When you call range() with three arguments, you can choose not only 
where the series of numbers will start and stop but also how big the 
difference will be between one number and the next.

range(start, stop, step)

If your 'step' is negative and 'start' is bigger than 'stop', then 
you move through a series of decreasing numbers.

for i in range(10,0,-1):
    print(i, end=' ')
# Output: 10 9 8 7 6 5 4 3 2 1

for i in range(10, -6, -2):
    print(i)

rop = input('Type a three or more word or code.')
t = len(rop)
j = ''
for i in range(t-1,-1,-1):
  j = j+rop[i]
print(j)