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Q:

reduce function using lambda in python

#filter function 

nums1 = [2,3,5,6,76,4,3,2]


bads = list(filter(lambda x: x>4, nums1))
print(bads)
1
#Reduce function

from functools import reduce
list2 =[1,2,3,4,5]
fins = reduce(lambda x,y:x+y, list2)
print(fins)

#o/p : 15 

# reduce similar to this concept
list2 =[1,2,3,4,5]
adds = 0
for i in list2:
    adds+=i
print(adds)
1

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