re.match() python

import re

pattern = '^a...s$'
test_string = 'abyss'
result = re.match(pattern, test_string)

if result:
  print("Search successful.")
else:
  print("Search unsuccessful.")	

import re
>>> m = re.search('(?<=abc)def', 'abcdef')
>>> m.group(0)
'def'

>>> import re
>>> m = re.search('(?<=abc)def', 'abcdef')
>>> m.group(0)
'def'

  ## Search for pattern 'bb' in string 'aabbcc'.
  ## All of the pattern must match, but it may appear anywhere.
  ## On success, match.group() is matched text.
  match = re.search(r'bb', 'aabbcc') # found, match.group() == "bb"
  match = re.search(r'cd', 'aabbcc') # not found, match == None

  ## . = any char but \n
  match = re.search(r'...c', 'aabbcc') # found, match.group() == "abbc"

  ## \d = digit char, \w = word char
  match = re.search(r'\d\d\d', 'p123g') # found, match.group() == "123"
  match = re.search(r'\w\w\w', '@@abcd!!') # found, match.group() == "abc"

result = re.sub('abc',  '',    input)           # Delete pattern abc
result = re.sub('abc',  'def', input)           # Replace pattern abc -> def
result = re.sub(r'\s+', ' ',   input)           # Eliminate duplicate whitespaces using wildcards
result = re.sub('abc(def)ghi', r'\1', input)    # Replace a string with a part of itself