import operator x = {1: 2, 3: 4, 4: 3, 2: 1, 0: 0} sorted_x = sorted(x.items(), key=operator.itemgetter(1)) # Sort by key import operator x = {1: 2, 3: 4, 4: 3, 2: 1, 0: 0} sorted_x = sorted(x.items(), key=operator.itemgetter(0))
x = {1: 2, 3: 4, 4: 3, 2: 1, 0: 0} {k: v for k, v in sorted(x.items(), key=lambda item: item[1])} {0: 0, 2: 1, 1: 2, 4: 3, 3: 4}
sortedDictionary = sorted(mydictionary.keys())
A={1:2, -1:4, 4:-20} {k:A[k] for k in sorted(A)} output: {-1: 4, 1: 2, 4: -20}
In [1]: import collections In [2]: d = {2:3, 1:89, 4:5, 3:0} In [3]: od = collections.OrderedDict(sorted(d.items())) In [4]: od Out[4]: OrderedDict([(1, 89), (2, 3), (3, 0), (4, 5)])
from operator import itemgetter new_dict = sorted(data.items(), key=itemgetter(1))
dictionary_items = a_dictionary.items() sorted_items = sorted(dictionary_items)
from collections import OrderedDict dd = OrderedDict(sorted(d.items(), key=lambda x: x[1])) print(dd)