Gerlinde
0
Q:

python set

>>> A = {0, 2, 4, 6, 8};
>>> B = {1, 2, 3, 4, 5};

>>> print("Union :", A | B)  
Union : {0, 1, 2, 3, 4, 5, 6, 8}

>>> print("Intersection :", A & B)
Intersection : {2, 4}

>>> print("Difference :", A - B)
Difference : {0, 8, 6}

# elements not present both sets
>>> print("Symmetric difference :", A ^ B)   
Symmetric difference : {0, 1, 3, 5, 6, 8}
9
# A set contains unique elements of which the order is not important
s = set()
s.add(1)
s.add(2)
s.remove(1)
print(s)
# Can also be created from a list (or some other data structures)
num_list = [1,2,3]
set_from_list = set(num_list)
4
set_example = {1, 2, 3, 4, 5, 5, 5}

print(set_example)

# OUTPUT
# {1, 2, 3, 4, 5} ----- Does not print repetitions
11
#help set the array in python in order
2
A_Set = {1, 2, "hi", "test"}

for i in A_Set: #Loops through the set. You only get the value not the index
  print(i) #Prints the current value
0
# of get() and set() method in 
# normal function 
  
class Geek: 
    def __init__(self, age = 0): 
         self._age = age 
      
    # getter method 
    def get_age(self): 
        return self._age 
      
    # setter method 
    def set_age(self, x): 
        self._age = x 
  
raj = Geek() 
  
# setting the age using setter 
raj.set_age(21) 
  
# retrieving age using getter 
print(raj.get_age()) 
  
0

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