python return first n key values pairs from dictionary

# Basic syntax:
{key: dictionary[key] for key in list(dictionary)[:number_keys]}

# Note, number_keys is the number of key:value pairs to return from the
#	dictionary, not including the number_keys # itself
# Note, Python is 0-indexed
# Note, this formula be adapted to return any slice of keys from the 
#	dictionary following similar slicing rules as for lists

# Example usage 1:
dictionary = {'a': 3, 'b': 2, 'c': 3, 'd': 4, 'e': 5}
{key: dictionary[key] for key in list(dictionary)[:2]}
--> {'a': 3, 'b': 2} # The 0th to 1st key:value pairs

# Example usage 2:
dictionary = {'a': 3, 'b': 2, 'c': 3, 'd': 4, 'e': 5}
{key: dictionary[key] for key in list(dictionary)[2:5]}
--> {'c': 3, 'd': 4, 'e': 5} # The 2nd to 4th key:value pairs

list(islice(d.iteritems(), n))
'Update for Python 3.6
list(islice(d.items(), n))