python list pop

// no pop methode for strings (strings are immutable)

a = "abc"

last_letter = a[-1]
a = a[:-1]

my_list = [123, 'Add', 'Grepper', 'Answer']
my_list.pop()
-->[123, 'Add', 'Grepper'] #last element is removed

my_list = [123, 'Add', 'Grepper', 'Answer']
my_list.pop(0)
-->['Add', 'Grepper', 'Answer'] #first element is removed

my_list = [123, 'Add', 'Grepper', 'Answer']
any_index_of_the_list = 2
my_list.pop(any_index_of_the_list)
-->[123, 'Add', 'Answer'] #element at index 2 is removed 
						  #(first element is 0)

array.pop(2) # removes element at index 2

# Python list method pop() removes
# and returns last object or obj from the list.
# .pop() last element .pop(0) first element

my_list = [123, 'Add', 'Grepper', 'Answer'];
print "Pop default: ", my_list.pop()
> Pop default:  Answer
# List updated to [123, 'Add', 'Grepper']
print "Pop index: ", my_list.pop(1)
> Pop index: Add
# List updated to [123, 'Grepper']

liste = ['a',1,2]
element = liste.pop()
=> element = 2
=> liste = ['a',1]
liste.pop(0)
=> element = 'a'
=> liste = [1]

#pop removes the last element
li=[1,2,3,4,5]
li.pop()
#>>>[1, 2, 3, 4]

# removes last element of list unless parameter is given
l1 = [1,2,3,4,5]
print(l1.pop()) # returns [1, 2, 3, 4]
print(l1.pop(2)) # returns [1, 2, 4, 5] removes element at given index