# any list a = [1, 7, 3, 12, 5] # index of minimum element # if more than 1 minimum, # first index is returned min_index = a.index(min(a)) # index of maximum element max_index = a.index(max(a))
import numpy as np x=[1,2,3,4,5] max_index=np.argmax(x) # return the index of the maximun element # max_index has the value 4
[i for i, x in enumerate(l) if x == max(l)]
