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Q:

python how to count the lines in a file

# Basic syntax:
count = len(open('/path/to/the/file.ext').readlines())
2
f = open("filename", "r") #Load file in any mode that's able to read, ie r, r+, w+ etc

#to get length
len(f.readlines())

#To iterate over each line
for line in f.readlines(): #file.readlines(), splits the file into a list, where each element is a seperate line
  print(line)
4
filename = "test.txt"
count = 0
with open(filename, 'r') as f:
    for line in f:
        count += 1
print("Total number of lines is:", count)
0
def countlines(fname,mode='r+'):
	count=0
	with open(fname) as f:
		for _ in f:
			count += 1
	print('total number of lines in file : ',count)

countlines('file1.txt')

##########################

with open('file1.txt') as f:
	print(sum(1 for _ in f))

###########################
'''You can use len(f.readlines()),
 but this will create an additional list in memory,
  which won't even work on huge files that don't fit in memory.

'''
0
def countlines(fname,mode='r+'):
	count=0
	with open(fname) as f:
		for _ in f:
			count += 1
	print('total number of lines in file : ',count)

countlines('file1.txt')

##########################

with open('file1.txt') as f:
	print(sum(1 for _ in f))
##########################
with open('file1.txt') as f:
	for lno , line in enumerate(f,1):
		pass
	print('total lines:',lno)

###########################
'''You can use len(f.readlines()),
 but this will create an additional list in memory,
  which won't even work on huge files that don't fit in memory.

'''
0

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