python get the key with the max or min value in a dictionary

a_dictionary = {"a": 1, "b": 2, "c": 3}

# get key with max value
max_key = max(a_dictionary, key=a_dictionary.get)

print(max_key)

# Basic syntax:
key_with_max_value = max(dictionary, key=dictionary.get)

# Note, to get the max value itself, you can do either of the following:
max_value = dictionary[max(dictionary, key=dictionary.get)]
max_value = max(dictionary.values())

# Example usage:
dictionary = {"a": 1, "b": 2, "c": 3}
max(dictionary, key=dictionary.get)
--> 'c'

import operator
stats = {'a':1000, 'b':3000, 'c': 100}
max(stats.iteritems(), key=operator.itemgetter(1))[0]

d = {'A': 4,'B':10}
min_v = min(zip(d.values(), d.keys()))
# min_v is (4,'A')

max_v = max(zip(d.values(), d.keys()))
# max_v is (10,'B')