python find factors of a number

def factors(x):
    for i in range (1 , x +1):
        if x % i == 0:
            print (i)

# Python Program to find the factors of a number

# This function computes the factor of the argument passed
def print_factors(x):
   print("The factors of",x,"are:")
   for i in range(1, x + 1):
       if x % i == 0:
           print(i)

num = 6

print_factors(num)

def factors(n):
    return set(reduce(list.__add__, \
        ([i, n//i] for i in range(1, int(n**0.5) + 1) if not n % i )))

# Python program to print prime factors 
  
import math 
  
# A function to print all prime factors of  
# a given number n 
def primeFactors(n): 
      
    # Print the number of two's that divide n 
    while n % 2 == 0: 
        print 2, 
        n = n / 2
          
    # n must be odd at this point 
    # so a skip of 2 ( i = i + 2) can be used 
    for i in range(3,int(math.sqrt(n))+1,2): 
          
        # while i divides n , print i ad divide n 
        while n % i== 0: 
            print i, 
            n = n / i 
              
    # Condition if n is a prime 
    # number greater than 2 
    if n > 2: 
        print n 
          
# Driver Program to test above function 
  
n = 315
primeFactors(n) 
  
# This code is contributed by Harshit Agrawal