python codes and answers cheat code pdf

values = (x * 2 for x in range(10000))
len(values)  # Error
for x in values: 

x = “Python”
len(x)
x[0]
x[-1]
x[0:3]
 
# Formatted strings
name = f”{first} {last}”
 
# Escape sequences
\” \’ \\ \n
 
# String methods
x.upper()
x.lower()
x.title()
x.strip()
x.find(“p”)
x.replace(“a”, “b”)
“a” in x

def increment(number, by=1):   
    return number + by
 
# Keyword arguments 
increment(2, by=1)
 
# Variable number of arguments 
def multiply(*numbers): 
    for number in numbers: 
        print number 
 
 
multiply(1, 2, 3, 4)
 
# Variable number of keyword arguments 
def save_user(**user):  
    ...
 
 
save_user(id=1, name="Mosh")

point = {"x": 1, "y": 2}
point = dict(x=1, y=2)
point["z"] = 3
if "a" in point: 
    ... 
point.get("a", 0)   # 0
del point["x"]
for key, value in point.items(): 
   ... 
 
# Dictionary comprehensions 
values = {x: x * 2 for x in range(5)}

a = 1       # integer
b = 1.1     # float
c = 1 + 2j  # complex number (a + bi)
d = “a”     # string
e = True    # boolean (True / False)

for n in range(1, 10): 
    print(n)
 
while n < 10: 
    print(n)
    n += 1

first = {1, 2, 3, 4}
second = {1, 5}
 
first | second  # {1, 2, 3, 4, 5}
first & second  # {1}
first - second  # {2, 3, 4}
first ^ second  # {2, 3, 4, 5}
 
if 1 in first: 
    ... 

if x == 1:  
    print(“a”)
elif x == 2:  
    print(“b”)
else:   
    print(“c”)
 
# Ternary operator 
x = “a” if n > 1 else “b”
 
# Chaining comparison operators
if 18 <= age < 65:

from array import array 
 
numbers = array("i", [1, 2, 3])

0
“”
[]