Q:

pandas df by row index

rowData = dfObj.loc[ 'b' , : ]
1
In [1]: df = pd.DataFrame(np.random.rand(5,2),index=range(0,10,2),columns=list('AB'))

In [2]: df
Out[2]: 
          A         B
0  1.068932 -0.794307
2 -0.470056  1.192211
4 -0.284561  0.756029
6  1.037563 -0.267820
8 -0.538478 -0.800654

In [5]: df.iloc[[2]]
Out[5]: 
          A         B
4 -0.284561  0.756029

In [6]: df.loc[[2]]
Out[6]: 
          A         B
2 -0.470056  1.192211
1
indices = [133, 22, 19, 203, 14, 1]
df_by_indices = df.iloc[indices, :]
1

New to Communities?

Join the community