def intersection(lst1, lst2): lst3 = [value for value in lst1 if value in lst2] return lst3 # Driver Code lst1 = [4, 9, 1, 17, 11, 26, 28, 54, 69] lst2 = [9, 9, 74, 21, 45, 11, 63, 28, 26] print(intersection(lst1, lst2))
>>> a = [1,2,3,4,5] >>> b = [1,3,5,6] >>> list(set(a) & set(b)) [1, 3, 5]
x = {"apple", "banana", "cherry"} y = {"google", "microsoft", "apple"} z = x.intersection(y) print(z) # Output: {"google"}
x = {"apple", "banana", "cherry"} y = {"google", "microsoft", "apple"} z = x.intersection(y) print(z) # Output: {"apple"}