how to print error in try except python

try:
  # some code
except Exception as e:
	print("ERROR : "+str(e))

try:
  print("I will try to print this line of code")
except:
  print("I will print this line of code if an error is encountered")

try:
  print("I will try to print this line of code")
except ERROR_NAME:
  print("I will print this line of code if error ERROR_NAME is encountered")

import traceback

dict = {'a':3,'b':5,'c':8}
try:
  print(dict[q])
 
except:
  traceback.print_exc()
  
# This will trace you back to the line where everything went wrong. 
# So in this case you will get back line 5    
  
  

try:
  # code block
except ValueError as ve:
  print(ve)

>>> def divide(x, y):
...     try:
...         result = x / y
...     except ZeroDivisionError:
...         print("division by zero!")
...     else:
...         print("result is", result)
...     finally:
...         print("executing finally clause")
...
>>> divide(2, 1)
result is 2.0
executing finally clause
>>> divide(2, 0)
division by zero!
executing finally clause
>>> divide("2", "1")
executing finally clause
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
  File "<stdin>", line 3, in divide
TypeError: unsupported operand type(s) for /: 'str' and 'str'

except:
    pass

  try:
  print(x)
except NameError:
  print("Variable x 
  is not defined")
except:
  print("Something else went 
  wrong") 

>>> 10 * (1/0)
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
ZeroDivisionError: division by zero
>>> 4 + spam*3
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
NameError: name 'spam' is not defined
>>> '2' + 2
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
TypeError: Can't convert 'int' object to str implicitly