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Q:

how to check if a list contains elements in another list

## checking all elements of list_B in list_A
list_A = [1, 2, 3, 4]
list_B = [2, 3]

check = all(item in list_A for item in list_B)

print(check)
# True
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## using set
list_A = [1, 2, 3, 4]
list_B = [2, 3]

set_A = set(list_A)
set_B = set(list_B)

print(set_A.intersection(set_B))

# True if there is any element same
# False if there is no element same
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## checking any elment of list_B in list_A
list_A = [1, 2, 3, 4]

list_B = [2, 3, 6]

check = any(item in list_A for item in list_B)

print(check)
# True
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## using set
list_A = [1, 2, 3, 4]
list_B = [5,1]

set_A = set(list_A)
set_B = set(list_B)

output = False if (set_A.intersection(set_B) == set()) else True
print(output)
# True if there is any element same
# False if there is no element same
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##Taking examples of two python lists.

##Take examples of two lists.

list1 = [2,4,0,7,6]
list2 = [1,0,9,7,6]

##the statement for condition is.

check = any(element in list2 for element in list1)
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