fizzbuzz python hackerrank solution

for (i=1; i<=100; i++) {
    console.log((i%3==0&&i%5==0)?"FizzBuzz":(i%3==0)?"Fizz" : (i%5==0)?"Buzz" : i);
}

def fizzBuzz(n):
    for i in range(1,n+1):
        if i % 3 == 0 and i % 5 == 0:
            print('FizzBuzz')
        elif i % 3 == 0:
            print('Fizz')
        elif i % 5 == 0:
            print('Buzz')
        else:
            print(i)