find leap year in python

#Write a program to prompt(input) year and check if it is leap year
year=int(input("enter the year to check:"))
if((year%4==0) and (year%100!=0)) or (year%400==0):
    print(year,"is a leap year")
else:
    print(year,"is not a leap year")    

import calendar
print(calendar.isleap(1900))