fastest way to check odd or even in python

# Python program to check if the input number is odd or even.
# A number is even if division by 2 gives a remainder of 0.
# If the remainder is 1, it is an odd number.

num = int(input("Enter a number: "))
if (num % 2) == 0:
   print("{0} is Even".format(num))
else:
   print("{0} is Odd".format(num))

injd = int(input('Enter a number'))
n = injd % 2
if n > 0:
  print('This is an odd number')
else:
  print('This is an even number')

>>> def isodd(num):
        return num & 1 and True or False

>>> isodd(10)
False
>>> isodd(9)
True