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Q:

dictionary comprehension python

square_dict = {num: num*num for num in range(1, 11)}
3
dict1 = {'a': 1, 'b': 2, 'c': 3, 'd': 4, 'e': 5}
# Double each value in the dictionary
double_dict1 = {k:v*2 for (k,v) in dict1.items()}
# double_dict1 = {'e': 10, 'a': 2, 'c': 6, 'b': 4, 'd': 8} <-- new dict
1
keys=['var1','var2','var3']
my_dict={key:np.zeros(10) for key in keys}
2
print({i:j for i,j in zip(txt_list,num) if i!="All"})
2
# Dictionary comprehension

{j:j*2 for i in range(10)}
0

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