string.count(substring, start, end) # Start and end is optional
def count_substring(string,sub_string): l=len(sub_string) count=0 for i in range(len(string)-len(sub_string)+1): if(string[i:i+len(sub_string)] == sub_string ): count+=1 return count
it counts the number of elements in the list or in the string(words)
string.count(substring, start=..., end=...) 'recede'.count('e') >>> 3 'recede'.count('e', 2, 4) >>> 1