argv in python

import sys
print("This is the name of the script:", sys.argv[0])
print("Number of arguments:", len(sys.argv))
print("The arguments are:" , str(sys.argv))

#Example output
#This is the name of the script: sysargv.py
#Number of arguments in: 3
#The arguments are: ['sysargv.py', 'arg1', 'arg2']

# Python program to demonstrate 
# sys.argv 
  
  
import sys 
  
print("This is the name of the program:", sys.argv[0]) 
  
print("Argument List:", str(sys.argv)) 

argv = sys.argv[1:]

#argv in python


import sys

print 'Number of arguments:', len(sys.argv), 'arguments.'
print 'Argument List:', str(sys.argv)

#command in cmd :
$ python test.py arg1 arg2 arg3

# producing following result :
Number of arguments: 4 arguments.
Argument List: ['test.py', 'arg1', 'arg2', 'arg3']

# arguments
def test_var_args(f_arg, *argv):
    print("first normal arg:", f_arg)
    for arg in argv:
        print("another arg through *argv :", arg)

test_var_args('yasoob','python','eggs','test')

# keywork arguments
def test_var_kwargs(f_arg, **kwargs):
  	print(f_arg)
    for (key, item) in kwargs.items():
      	print("Keyword: ", key)
        print("Value: ", item)

test_var_kwargs('yasoob', x = 12)