append to lists python

# Basic syntax:
your_list.append('element_to_append')

# Example usage:
your_list = ['a', 'b']
your_list.append('c')
print(your_list)
--> ['a', 'b', 'c']

# Note, .append() changes the list directly and doesn’t require an 
#	assignment operation. In fact, the following would produce an error:
your_list = your_list.append('c')

  list = ['larry', 'curly', 'moe']
  list.append('shemp')         ## append elem at end
  list.insert(0, 'xxx')        ## insert elem at index 0
  list.extend(['yyy', 'zzz'])  ## add list of elems at end
  print list  ## ['xxx', 'larry', 'curly', 'moe', 'shemp', 'yyy', 'zzz']
  print list.index('curly')    ## 2

  list.remove('curly')         ## search and remove that element
  list.pop(1)                  ## removes and returns 'larry'
  print list  ## ['xxx', 'moe', 'shemp', 'yyy', 'zzz']

#makes an empty list
List = []

#appends "exaple" to that list
List.append(example)

#removes "example" from that list
List.remove(example)

list = ["a"]
list.append("b")

print(list)
["a","b"]

 list = []          ## Start as the empty list
  list.append('a')   ## Use append() to add elements
  list.append('b')

stuff = ["apple", "banana"]
stuff.append("carrot")
# Print to see if it worked
print(stuff)
# You can do it with a variable too
whatever = "pineapple"
stuff.append(whatever)
# Print it again
print(stuff)

list1 = ["hello"]
list1 = list1 + ["world"]

 list = [1, 2, 3]
  print list.append(4)   ## NO, does not work, append() returns None
  ## Correct pattern:
  list.append(4)
  print list  ## [1, 2, 3, 4]

 list = ['a', 'b', 'c', 'd']
  print list[1:-1]   ## ['b', 'c']
  list[0:2] = 'z'    ## replace ['a', 'b'] with ['z']
  print list         ## ['z', 'c', 'd']

list_of_Lists = [[1,2,3],['hello','world'],[True,False,None]]
list_of_Lists.append([1,'hello',True])
ouput = [[1, 2, 3], ['hello', 'world'], [True, False, None], [1, 'hello', True]]