ela
0
Q:

function return time ago php

public function convert_time_to_days($date) {
       $current_date = date("Y-m-d H:m:s");
       $time = array();
       $day = floor((strtotime($current_date) - strtotime($date)) / (60 * 60 * 24));
 
       if ($day == 0) {
           $hour = floor((strtotime($current_date) - strtotime($date)) / (60 * 60));
 
           if ($hour == 0) {
               $minute = floor((strtotime($current_date) - strtotime($date)) / (60));
               $time = $minute . __d('course', "minutes ago");
 
           } else {
               $time = $hour . __d('course', "hours ago");
           }
      
       } else {
           $time = $day . __d('course', "days ago");
       }
      
       return $time;
   }
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