Q:

spread and rest operator javascript

function sum(...numbers) {
	return numbers.reduce((accumulator, current) => {
		return accumulator += current;
	});
};
 
sum(1,2) // 3
sum(1,2,3,4,5) // 15
3
var myName = ["Marina" , "Magdy" , "Shafiq"] ;const [firstName , ...familyName] = myName ;console.log(firstName); // Marina ;console.log(familyName); // [ "Magdy" , "Shafiq"] ;
1
function sum(x, y, z) {
  return x + y + z;
}

const numbers = [1, 2, 3];

console.log(sum(...numbers));
// expected output: 6

console.log(sum.apply(null, numbers));
// expected output: 6
3
var myName = ["Marina" , "Magdy" , "Shafiq"];var newArr = [...myName ,"FrontEnd" , 24];console.log(newArr) ; // ["Marina" , "Magdy" , "Shafiq" , "FrontEnd" , 24 ] ;
0
function myData(...args){console.log(args) ; // ["Marina",24,"Front-End Developer"]}myData("Marina",24,"Front-End Developer") ;
-1

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