0
Q:

js array sum

const sum = arr => arr.reduce((a, b) => a + b, 0);
8
arrSum = function(arr){  return arr.reduce(function(a,b){    return a + b  }, 0);}
1
[1, 2, 3, 4].reduce((a, b) => a + b, 0)

// Output: 10
3
const arrSum = arr => arr.reduce((a,b) => a + b, 0)
8
function getArraySum(a){
    var total=0;
    for(var i in a) { 
        total += a[i];
    }
    return total;
}

var payChecks = [123,155,134, 205, 105]; 
var weeklyPay= getArraySum(payChecks); //sums up to 722
5
const summation = (n) => (n * (n + 1)) / 2;
1
console.log(
  [1, 2, 3, 4].reduce((a, b) => a + b, 0)
)
console.log(
  [].reduce((a, b) => a + b, 0)
)
4

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