Q:

javascript sort alphabetically

var items = ['réservé', 'premier', 'communiqué', 'café', 'adieu', 'éclair'];
items.sort(function (a, b) {
  return a.localeCompare(b); //using String.prototype.localCompare()
});

// items is ['adieu', 'café', 'communiqué', 'éclair', 'premier', 'réservé']
3
users.sort((a, b) => a.firstname.localeCompare(b.firstname))
2
//sort array alphabetically
objArray.sort(function(a, b) {
   return a.localeCompare(b);
});
1
// Alphabetically
const ascending = data.sort((a, b) => a[field].localeCompare(b[field]))
// Descending
const descending = ascending.reverse()
1
var items = ['réservé', 'premier', 'communiqué', 'café', 'adieu', 'éclair'];
items.sort((a, b) =>
   a.localeCompare(b)//using String.prototype.localCompare()
);
0

        
            
        
     let numbers = [0, 1, 2, 3, 10, 20, 30];
numbers.sort((a, b) => a - b);

console.log(numbers);
0
var fruits = ["Banana", "Orange", "Apple", "Mango"];
fruits.sort();
1
function sortNumbers(a, b) {
  return a - b;
}
var ages = [12, 95, 43, 15, 10, 32, 65, 78, 8];
ages.sort(sortNumbers); //ages is now sorted low to high
//console.log(ages); [8, 10, 12, 15, 32, 43, 65, 78, 95]
0

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