0
Q:

javascript reduce promises

const sum = await [
  Promise.resolve(1),
  Promise.resolve(1),
  Promise.resolve(1)
].reduce(async (previousPromise, itemPromise) => {
  const sum = await previousPromise;
  const item = await itemPromise;
  return sum + item;
}, Promise.resolve(0))

// sum === 3
1

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