0
Q:

javascript factor chain

function factorChain(arr) {
	for (let i = 0; i < arr.length - 1; i++) {
		if ((arr[i + 1] % arr[i]))
			return false
	}
	return true
}
0
function factorChain (arr) {
	return arr.reduce((a, c, i) => arr[i] % arr[i-1] === 0);
}
0
function calculate(num) {
    var str = "0";
    for (var i = 1; i <= num; i++) {
        if (num % i == 0) {
            str += ',' + i;
        }
    }
    alert(str);
}

calculate(232);
0
function factorChain(num) {
 let n = num.slice(num.length - 1, num.length)[0]
 return [...Array(n + 1).keys()]
	 .filter(v => n % v === 0)
	 .map((v, i) => v === num[i])[0]
}
0
const factors = number => [...Array(number + 1).keys()].filter(i=>number % i === 0);
console.log(factors(36));      //  [1, 2, 3, 4, 6, 9, 12, 18, 36]
0
const factors = number => Array
    .from(Array(number + 1), (_, i) => i)
    .filter(i => number % i === 0)

 console.log(factors(36));      //  [1, 2, 3, 4, 6, 9, 12, 18, 36]
0

New to Communities?

Join the community