Q:

find method javascript

const inventory = [
  {name: 'apples', quantity: 2},
  {name: 'cherries', quantity: 8}
  {name: 'bananas', quantity: 0},
  {name: 'cherries', quantity: 5}
  {name: 'cherries', quantity: 15}
  
];

const result = inventory.find( ({ name }) => name === 'cherries' );

console.log(result) // { name: 'cherries', quantity: 5 }
11
const simpleArray = [3, 5, 7, 15];
const objectArray = [{ name: 'John' }, { name: 'Emma' }]

console.log( simpleArray.find(e => e === 7) )
// expected output 7

console.log( simpleArray.find(e => e === 10) )
// expected output undefined

console.log( objectArray.find(e => e.name === 'John') )
// expected output { name: 'John' }
4
// To find a specific object in an array of objects
myObj = myArrayOfObjects.find(obj => obj.prop === 'something');
9
const array1 = [5, 12, 8, 130, 44];

const found = array1.find(element => element > 10);

console.log(found);
// expected output: 12
6
const inventory = [
  {name: 'apples', quantity: 2},
  {name: 'bananas', quantity: 0},
  {name: 'cherries', quantity: 5}
];

function isCherries(fruit) { 
  return fruit.name === 'cherries';
}

console.log(inventory.find(isCherries)); 
// { name: 'cherries', quantity: 5 }
0
The first element that will be found by that function
const f = array1.find(e => e > 10);
1
myArray.filter(x => x > 5)
0
myArray.find(x => x.id === '45').foo;
0
array.find(function(element))
0
function isBigEnough(element) {
  return element >= 15;
}

[12, 5, 8, 130, 44].find(isBigEnough); // 130
0

 var ages = [3, 10, 18, 20];

function checkAdult(age) {
  return age >= 18;
}

function myFunction() {

    document.getElementById("demo").innerHTML = ages.find(checkAdult);
} 
1

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