revese the linked list java

/*
public class ListNode {
    public int val;
    public ListNode next;
    public ListNode(int x) { val = x; next = null; }
}
*/

public static ListNode[] reverse_linked_list(ListNode head) {

        ListNode prev = null;
        ListNode current = head;
        ListNode next;

        ListNode tail = head;

        while (current != null) {

            next = current.next;
            current.next = prev;
            prev = current;
            current = next;
        }

        head = prev;

        ListNode[] result = {head, tail};

        return result;
}

// Iterative C++ program to reverse 
// a linked list 
#include <iostream> 
using namespace std; 
  
/* Link list node */
struct Node { 
    int data; 
    struct Node* next; 
    Node(int data) 
    { 
        this->data = data; 
        next = NULL; 
    } 
}; 
  
struct LinkedList { 
    Node* head; 
    LinkedList() 
    { 
        head = NULL; 
    } 
  
    /* Function to reverse the linked list */
    void reverse() 
    { 
        // Initialize current, previous and 
        // next pointers 
        Node* current = head; 
        Node *prev = NULL, *next = NULL; 
  
        while (current != NULL) { 
            // Store next 
            next = current->next; 
  
            // Reverse current node's pointer 
            current->next = prev; 
  
            // Move pointers one position ahead. 
            prev = current; 
            current = next; 
        } 
        head = prev; 
    } 
  
    /* Function to print linked list */
    void print() 
    { 
        struct Node* temp = head; 
        while (temp != NULL) { 
            cout << temp->data << " "; 
            temp = temp->next; 
        } 
    } 
  
    void push(int data) 
    { 
        Node* temp = new Node(data); 
        temp->next = head; 
        head = temp; 
    } 
}; 
  
/* Driver program to test above function*/
int main() 
{ 
    /* Start with the empty list */
    LinkedList ll; 
    ll.push(20); 
    ll.push(4); 
    ll.push(15); 
    ll.push(85); 
  
    cout << "Given linked list\n"; 
    ll.print(); 
  
    ll.reverse(); 
  
    cout << "\nReversed Linked list \n"; 
    ll.print(); 
    return 0; 
} 

Easiest way


public static LinkedList reverse(LinkedList head) {
		LinkedList prevAddress = null;
		LinkedList currentAddress = head;
		LinkedList nextAddress = head.next;
		
		while(nextAddress!=null) {
			currentAddress.next = prevAddress;
			prevAddress = currentAddress;
			currentAddress = nextAddress;
			nextAddress= currentAddress.next;
			currentAddress.next = prevAddress;
		}
		head = currentAddress;
		return head;
	}
    
Just try to visualize its all about pointers game. :-)
  NO GFG ANSWER