pal-meto
0
Q:

c# try

try
{
  int[] myNumbers = {1, 2, 3};
  Console.WriteLine(myNumbers[10]);
}
catch (Exception e)
{
  Console.WriteLine(e.Message);
}
15
try 
{
  //  Block of code to try
}
catch (Exception e)
{
  //  Block of code to handle errors
}
0

        try
        {
            ProcessString(s);
        }
        catch (Exception e)
        {
            Console.WriteLine("{0} Exception caught.", e);
        }
    }
}
/*
Output:
System.ArgumentNullException: Value cannot be null.
   at TryFinallyTest.Main() Exception caught.
 * */
1

// ------------ How to use Try, Catch and Finally? --------------- //
// This is often used whenever you want to prevent your program from 
// crashing due to an incorrect input given by the user 


// --->  TRY 
// Where you put the part of your code that can cause problems

// --->  CATCH
// The parameter of this will indicate which "exception" was the 
// root of the problem. If you don't know the cause, then you can 
// make this general, with just: catch (Exception).

// --->  FINALLY
// This block of code will always run, regardless of whether 
// "try" or "catch" were trigger or not


using System;

namespace teste2
{
    class Program
    {
        static void Main(string[] args)
        {
            Console.WriteLine("Enter a Number:");

            string input = Console.ReadLine();

            try
            {
                int inputNumber = int.Parse(input);  // if there is an error during the conversion, then we jump to a "catch" 
                Console.WriteLine("The power of value {0} is {1}", inputNumber, inputNumber * inputNumber);  
            }
            catch (FormatException)
            {
                Console.WriteLine("Format Exception detected: The input needs to be a number");
            }
            catch (OverflowException)
            {
                Console.WriteLine("Overflow Exception detected: The input can't be that long");
            }
            catch (ArgumentNullException)
            {
                Console.WriteLine("Argument Null Exception detected: The input can't be null");
            }
            finally
            {
                Console.ReadKey();
            }
    
        }
    }
}
1

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