nn0p
0
Q:

how to get size of 2d vector in c++

#include<bits/stdc++.h> 
using namespace std; 
  
int main(){ 
    int n = 3; 
    int m = 4; 
  
    // Create a vector containing n 
    //vectors of size m.  
    vector<vector<int> > vec( n , vector<int> (m, 0));  
  
    for (int i = 0; i < n; i++) { 
        for (int j = 0; j < m; j++){ 
            cout<< vec[i][j]<< " "; 
        } 
        cout<< "\n"; 
    } 
  
return 0; 
} 
0
// Create a vector containing n 
//vectors of size m, all u=initialized with 0
vector<vector<int> > vec( n , vector<int> (m, 0));  
4
auto M = 4;	// num of rows
auto N = 3; // num of cols in each row
auto default_value = 1; // default value of all int elements
std::vector<std::vector<int>> matrix(M, std::vector<int>(N, default_value));
1
myVector[
  Vector[0, 4, 2, 5],
  Vector[1, 4, 2]
];

/*When you call for myVector[1].size() it would return 3 and [0] would return 4.

For the amount of rows (int vectors) in the 2d vector, you can just use myVector.size()

You can run this to see it in actions*/
2
// finding size of a square matrix
myVector[0].size();
1

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