user3839936
0
Q:

declaring 2d dynamic array c++

int** a = new int*[rowCount];
for(int i = 0; i < rowCount; ++i)
    a[i] = new int[colCount];
2
int** arr = new int*[10]; // Number of Students
int i=0, j;
for (i; i<10; i++) 
	arr[i] = new int[5]; // Number of Courses
/*In line[1], you're creating an array which can store the addresses
  of 10 arrays. In line[4], you're allocating memories for the 
  array addresses you've stored in the array 'arr'. So it comes out 
  to be a 10 x 5 array. */
2
int** arr = new int*[10]; // Number of Students
int i=0, j;
for (i; i<10; i++) 
	arr[i] = new int[5]; // Number of Courses
In line[1], you're creating an array which can store the addresses
  of 10 arrays. In line[4], you're allocating memories for the 
  array addresses you've stored in the array 'arr'. So it comes out 
  to be a 10 x 5 array. 
3
#include <array>
2 #include <iostream>
3
4 using namespace std;
5
6 //remember const!
7 const int ROWS = 2;
8 const int COLS = 3;


int main(){
 array<array<int, COLS>, ROWS> matrix = {
 1, 2, 3,
 4, 5, 6
 };
  
  
  return 0;
}
0

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